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问题内容
我正在尝试创建我的第一个与 go 交叉编译的 rpm 包。
这是包含所有必需信息的 makefile:
appname?=helloworld
version?=v1.0.0
appandver := ${appname}-$(version)
# build flags
ldflags := -ldflags "-s -w -x=main.version=$(version)"
# temporary directory for common files when creating tarballs
releasetmpdir := $(shell mktemp -d -t ${appname}-${version}-release-xxxxxx)
# cross-compile to these cpus
# https://golang.org/doc/install/source#environment
linux_archs := amd64 arm arm64 ppc64 ppc64le
default: release-bin
main.go:
@echo 'package main' > $@
@echo 'import "fmt"' >> $@
@echo '// replaced with version when building' >> $@
@echo 'var version = "v0.0.0"' >> $@
@echo 'func main() {' >> $@
@echo ' fmt.println("hello, world!")' >> $@
@echo '}' >> $@
@go fmt $@
readme.md:
@echo 'this is a readme for $(appname) $(version)' > $@
@echo '$(appname) simply prints "hello, world!"' >> $@
license:
@echo 'you can do what ever you want with $(appname).' > $@
@echo 'you have all the responsibility!' >> $@
# build for all listed architectures
linux-build: main.go
@for arch in $(linux_archs); do \
echo "gnu/linux build... $$arch"; \
cgo_enabled=0 goos=linux goarch=$$arch go build $(ldflags) -v -o ./bin/linux-$$arch/${appname} . ; \
done
# copy common files used in binary tarball releases
copycommon: readme.md license
@echo "copying common files to temporary release directory '$(releasetmpdir)'.."
@mkdir "$(releasetmpdir)/bin"
@cp -v "license" "$(releasetmpdir)"
@cp -v "readme.md" "$(releasetmpdir)"
@mkdir --parents "$(pwd)/release/${version}"
# create binary release tarballs for each cpu architecture
compress-linux: linux-build
@for arch in $(linux_archs); do \
echo "gnu/linux tar... $$arch"; \
cp -v "$(pwd)/bin/linux-$$arch/${appname}" "$(releasetmpdir)/bin"; \
cd "$(releasetmpdir)"; \
tar --numeric-owner --owner=0 --group=0 -zcvf "$(pwd)/release/${version}/$(appandver)-linux-$$arch.tar.gz" . ; \
rm "$(releasetmpdir)/bin/${appname}"; \
done
# move all to temporary directory and compress with common files
compress-everything: copycommon compress-linux
@echo "$@ ..."
rm -rf "$(releasetmpdir)/*"
# create tarballs which has common files and different bin/${appname} per cpu architecture
release-bin: linux-build compress-everything
@echo "release done..."
# linux distributions
release-ldistros: ldistro-rpm
@echo "linux distros release done..."
release/linux/rpm:
@mkdir --parents ./release/linux/rpm
# rpm spec file (probably wrong)
release/linux/rpm/package.spec: release/linux/rpm
@echo 'name: ${appname}' > $@
@echo 'version: %{_version}' >> $@
@echo 'release: 1%{?dist}' >> $@
@echo 'summary: hello world' >> $@
@echo 'url: Https://example.org/${appandver}/' >> $@
@echo 'group: applications/utilities' >> $@
@echo 'license: apache-2.0' >> $@
@echo '%description' >> $@
@echo '${appname} is a command line program which prints "hello, world!"' >> $@
@echo '%setup -q' >> $@
@echo '%clean' >> $@
@echo '%files' >> $@
@echo '%license /usr/share/licenses/%{name}/license' >> $@
@echo '%doc /usr/share/doc/%{name}/readme.md' >> $@
@echo '/usr/bin/${appname}' >> $@
@echo '%install' >> $@
@echo 'install -dm755 "usr/bin/%{name}" -t "/usr/bin"' >> $@
# create rpm package for each cpu architecture from tarballs (probably wrong)
ldistro-rpm: "release/linux/rpm/package.spec
@for arch in $(linux_archs); do \
echo "generating rpm... $$arch"; \
tempdir=$$(mktemp -d -t $(appandver)-rpm-xxxxxx) ; \
echo " >> using temporary directory $$tempdir" ; \
cd "$$tempdir" ; \
mkdir --parents {sources,rpms,specs,srpms,build,tmp} ; \
cp "$(pwd)/release/linux/rpm/package.spec" "specs/${appname}" ; \
cd "build"; \
echo " >> extracting source binary package.." ; \
tar -xzf "$(pwd)/release/${version}/$(appandver)-linux-$$arch.tar.gz" . ; \
echo " >> generating directory structure in temp dir.." ; \
mkdir --parents ./usr/bin/ ; \
mv ./bin/${appname} ./usr/bin/ ; \
rm -rf ./bin ; \
mkdir --parents ./usr/share/licenses/${appname}/ ; \
mv license ./usr/share/licenses/${appname} ; \
mkdir --parents ./usr/share/doc/${appname}/ ; \
mv readme.md ./usr/share/doc/${appname} ; \
cd .. ; \
echo " >> building rpm package.." ; \
sudo rpmbuild -vv --nosignature --nodebuginfo --dbpath "$$tempdir" --root "$$tempdir" --buildroot "./build" --target $$arch --define "_tmppath /tmp" --define "_topdir ." --define "_version ${version}" --define "_buildhost localhost" --define "_rpmfilename $(appandver)-$$arch.rpm" -bb "specs/${appname}" && \
rpm -qlp --info "./rpms/$(appandver)-$$arch.rpm" && \
cp "./rpms/$(appandver)-$$arch.rpm" "$(pwd)/release/${version}/" ; \
echo "------------------------------------------------------------"; \
done
创建 bin/$os-$cpuarch/$appname 二进制文件:
% make linux-build
创建二进制源 tarball 到 release/$version/$appname-$version-$os-$cpuarch.tar.gz:
% make compress-everything
在 tarball 内创建文件树结构:
bin/$appname (different for each architecture)
license
readme.md
此结构被锁定,因为也有不同的操作系统 tarball。出于可读性原因,在此最小化示例中删除了不同的操作系统构建目标。
为每个 cpu 架构生成 rpm:
% make ldistro-rpm
当前的问题是,在 rpm 构建期间,实际的可执行文件被安装到正在运行的系统中。据我所知,这不应该发生。规范文件或 ldistro-rpm 目标中可能缺少什么?另外,一些 rpmbuild 示例似乎只使用 -bb 参数,但我找不到示例或弄清楚如何修改 spec 文件以便可以工作。 ldistro-rpm 目标似乎过于复杂。某些命令是否应该位于规范文件的 %install、%prep 等中?您能否以某种方式使用 spec 文件中的 source0 并将其指向 tarball,而不是在 ldistro-rpm 目标中生成目录结构?
解决方案
@echo 'install -Dm755 "usr/bin/%{NAME}" -t "/usr/bin"'
是您要安装到 /usr/bin 的位置。您应该安装到 $rpm_build_root/usr/bin。
以上就是本文的全部内容了,是否有顺利帮助你解决问题.